49x^2+8=44

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Solution for 49x^2+8=44 equation:



49x^2+8=44
We move all terms to the left:
49x^2+8-(44)=0
We add all the numbers together, and all the variables
49x^2-36=0
a = 49; b = 0; c = -36;
Δ = b2-4ac
Δ = 02-4·49·(-36)
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7056}=84$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-84}{2*49}=\frac{-84}{98} =-6/7 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+84}{2*49}=\frac{84}{98} =6/7 $

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